Question

请数学老师和学霸帮忙解答一下，图片上的这几道题，谢谢!

Answer 1

解如图。

Answer 2

⑴解:原式=2310÷[235-160÷40]
=2310÷[235-4]
=2310÷231
=10;

⑵解:原式=125×125×(800+1)
=125×800+125×1
=100000+125
=100125;

⑶解:原式=(235+265)+(649+351)
=500+1000
=1500;

⑷解:原式=39×65+39×45+39×1
=39×(65+45-1)
=39×（100+9）
=39×100+39×9
=3900+351
=4251.

Answer 3

如图

Answer 4

图

Answer 5

2310÷[235-160÷(21+19)]
=2310÷[235-160÷40]
=2310÷[235-40]
=2310÷195
=11.846153846153848

125×801
=125×(800+1)
=125×800+125×1
=100000+125
=100125

235+649+351+265
=(235+265)+(649+351)
=500+1000
=1500

39×65+45×39-39
=39×(65+45)-39
=39×110-39
=39×(100+10)-39
=39×100+39×10-39
=3900+390-39
=4290-39
=4251

追答

2310÷[235-160÷(21+19)]
=2310÷[235-160÷40]
=2310÷[235-4]
=2310÷231
=10