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(3x^2-x+8)/[(x-1)(x^2+4)]≡A/(x-1) +(Bx+C)/(x^2+4)
=>
3x^2-x+8≡A(x^2+4) +(Bx+C)(x-1)
x=1, =>A=10/5 =2
coef. of constant
4A-C = 8
8-C=8
C=0
ans : c
=>
3x^2-x+8≡A(x^2+4) +(Bx+C)(x-1)
x=1, =>A=10/5 =2
coef. of constant
4A-C = 8
8-C=8
C=0
ans : c
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