Question

3K(K-1)(K-2)=2(K+1)K+6K(K-1)的K等于几？

Answer 1

一、等式右侧变换
2(K+1)K+6K(K-1)
= 2K^2 +2K+6K^2-6K
= 8K^2 - 4K
= 4K(K-1)
二、带回题目中渣瞎等式
3K(K-1)(K-2) = 4K(K-1)
当 K≠0、且轮梁腊K≠1时， 有 3(k-2)=4
=> k=10/3
答腊滑案为： k=10/3，且 当 K≠0、K≠1

Answer 2

3K(K-1)(K-2)=2(K+1)K+6K(K-1)
3K(K-1)(K-2)-2(K+1)K-6K(K-1)=0
K[3(K-1)(K-2)-2(K+1)-6(K-1)]=0
K1=0
3(K-1)(K-2)-2(K+1)-6(K-1)=0
3(K²-3K+2)-2(K+1)-6(K-1)=0
3K²-9K+6-2K-2-6K+6=0
3K²-17K+10=0
（3K-2）庆余饥（K-5）=0
K2=2/誉返毁码3
K3=5

Answer 3

3K(K-1)(K-2)=2(K+1)K+6K(K-1)
解：3k(k^2-3k+2)=2k^2+2k+6k^2-6k
3k^3-9k^2+6k=8k^2-4k
3k^3-17k^2+10k=0
k(3k^2-17k+10)=0
k(3k-2)(k-5)=0
k1=0，k2=2/3，神禅纯袭段k3=5。游咐

Answer 4

3k(k-1)(k-2)=2(k+1)k+6k(k-1)
3k(k-1)(k-2)=2k.[(k+1)+3(k-1)]
3k(k-1)(k-2)=2k.(4k-2)
3k(k-1)(k-2)-4k.(2k-1)=0
k[3(k-1)(k-2) -4(2k-1) ]=0
k( 3k^2 -9k +6 - 8k+4 )=0
k( 3k^2 -17k +10 )=0
k(k-5)(3k-2)=0
k=0 or 5 or 2/3