Question

复合函数的求导

见下题，请问这个函数的导数怎么求？？

Answer 1

y = ln[(x-2)^(1/3)/√(1+x^2)] , 定义域 x > 2,
y = (1/3)ln(x-2) - (1/2)ln(1+x^2)

y' = (1/3)/(x-2) - x/(1+x^2)