Question

C语言 输入10个数，统计正数，负数及零的个数并输出正数累加和与个数累加和

急需，一个小时内解决

Answer 1

main()
{ int a,i,j,k,suma,sumb;
b=0;/*b用来统计输入数据的个数*/
i=j=k=0; /*i,j,k分别用来统计正数，负数和零的个数*/
suma=sumb=0; /*suma,sumb分别用来计算正数和负数的和*/
do{ /*循环体的内容是输入数据后，判断再累加*/
scanf("%d",&a);
if(a>0) {i++; suma+=a;} /*正数*/
else if(a<0) { j++; sumb+=a; } /*负数*/
else k++; /*零*/
} while(++b<10); /*循环控制10次*/

printf("zhengshu is %d ge ,the sum is %d\n",i,suma); /*输出*/
printf("fushu is %d ge ,the sum is %d\n",j,sumb);
printf("0 is %d ge \n",k);
}

Answer 2

#include<stdio.h>

void main()
{
int zheng=0,fu=0,ling=0;

int num;

scanf("%d",&num);

while(num!=9527)
{
if(num>0)
zheng++;
if(num==0)
ling++;
else
fu++;

}
printf("%d %d %d\n",zheng,fu,ling);

}

Answer 3

#include "stdio.h"
main()
{
int a[10],i,sum,q,w,e,r;
q=0;
w=0;
e=0;
r=0;
sum=0;
printf("Please input 10 numbers:\n");
for(i=0;i<10;i++)
scanf("%d",&a[i]);
for(i=0;i<10;i++)
{
if(a[i]>0)
{
sum=sum+a[i];
r=r+1;
}
if(a[i]==0)
q=q+1;
if(a[i]<0)
w=w+1;
}
printf("The bigger 0 sum is:%d,total :%d\n",sum,r);
printf("The equal 0 is:%d/n",q);
printf("The lower 0 is %d/n",w);
getchar();

}