Question

c语言编程题，计算1×2×3＋3×4×5＋······＋99×100×101的值

我急需要答案，各位哥哥姐姐闷，拜托了，多谢

Answer 1

这里用三种方法解决。只需要输入N的值就行了。上面这个题输入101就行了。

#include <stdio.h>

int main()
{
int n;
printf("please enter the number:(numbers only)\n");
scanf("%d",&n);
int i;
long fact;

fact=n;
for(i=1;i<n;i++)
{
fact*=i;
}
printf("The factorial of %d is %ld.\n",n,fact);

fact=n;
i=1;
while(i<n)
{
fact*=i;
i++;
}
printf("The factorial of %d is %ld.\n",n,fact);
fact=n;
i=1;
do{
fact*=i;
i++;
}while(i<n);
printf("The factorial of %d is %ld.\n",n,fact);

getchar();

}

已经调试过了，在GCC下面正确编译，在TC下面一定没有问题。

Answer 2

# include<stdio.h>
void main()
{
long value=0 , temp;
int i;
for(i=1 ; i<= 99 ; i+=2)
{temp=i*(i+1)*(i+2);
value+= temp;
}
printf("%ld",value);
}

Answer 3

这个很简单啊，用循环能搞定的
int j=1,k=0;
for(int i=1;i<=99;i++)
{
j=i*(i+1)*(i+2);
k=j+k;
}
cout<<"The result is:"<<k<<endl;

VS2005里调试通过，没有问题

Answer 4

#include <stdio.h>
void main()
{
int i,j ,sum=0;
for(i=1;1<=99;i=i+2)
j=i*(i+1)*(i+2);
sum=sum+j;
printf("%d\n",sum)
}

Answer 5

#include <stdio.h>

main
{
int a,b,c,n;
n=0;
a=1;
b=2;
c=3;

for(int m=1;m<=99;m++)
{
int s;
s=a*b*c;
a++;
b++;
c++;
n=n+s;
}

printf("和为：d%",n);

}