Question

dTree 的一个问题

intermediaryTree._buildTree = function(intermediaryNo,parentIntermediaryNo){
$(".intermediaryTree-ctn").empty();
dtTree = new dTree('dtTree');
dtTree.add(0,-1,'居间人');
for( var i = 0; i < objectAry.length ; i++ )
{
if(objectAry[i].id == intermediaryNo){
//dtree.add(id,pid,name,'','','','','',true);
dtTree.add(objectAry[i].id, parentIntermediaryNo ,objectAry[i].name,'','','','','',true);
}else{
dtTree.add(objectAry[i].id, objectAry[i].parentId ,objectAry[i].name,"");
}
}
$(".intermediaryTree-ctn").append(dtTree.toString());
};

这棵树我已经加载出来了，intermediaryNo 就是当前节点的id,但是我需要在加载完这棵树的时候，自动打开并且选中某个节点，
dtTree.openTo(intermediaryNo,true); 我用过了，但是不管用，希望大婶解答，坐等。

Answer 1

$(".intermediaryTree-ctn").append(dtTree.toString());
// 添加到页面之后执行openTo
dtTree.openTo(intermediaryNo,true);