Question

C++编程题：输入10个学生的姓名、学号和成绩,输出学生的成绩等级和不及格人数。

Answer 1

#include<iostream>

#include<string>

using namespace std;

const int n=10;                 

string name[n];                    //定义姓名数组

int num[n],score[n];           //定义学号和成绩数组

int main()

{int i;

 void input_data();

 int_data();

 cout<<endl<<"不及格名单："<<endl;

 for(i=0;i<n;i++)

      if(score[i]<60)

           cout<<"name[i]"<<" "<<"num[i]"<<" "<<score[i]<<endl;

      return 0;

}

viod input_data()

{int i;

 for(i=0;i<n;i++)

      {cout<<"请输入学生的姓名、学号和成绩"<<i+1<<"：";

        cin>>name[i]>>num[i]>>score[i];

      }

      return 0;

}

Answer 2

#include<iostream>
#include<string>
#include<cstring>
using namespace std;
struct Student
{
string name;
double acct;
double score;
};
int main()
{
Student students[10];
int counts=0;
int countA=0;
int countB=0;
int countC=0;
int countD=0;
for(int i=0;i<10;i++)
{
cout<<"Enter students"<<i+1<<" name : "<<endl;
getline(cin,students[i].name);
cout<<"Enter students"<<i+1<<" acct: "<<endl;
cin>>students[i].acct;
cout<<"Enter students"<<i+1<<" score: "<<endl;
cin>>students[i].score;
while(cin.get()!='\n')
continue;
}
for(int i=0;i<10;i++)
{
if(students[i].score<60)
countD++;
else if(students[i].score<70)
countC++;
else if(students[i].score<80)
countB++;
else if(students[i].score<90)
countA++;
else
counts++;
}
cout<<"not pass: "<<countD<<endl;
cout<<"60~70: "<<countC<<endl;
cout<<"70~80: "<<countB<<endl;
cout<<"80~90: "<<countA<<endl;
cout<<"90~100: "<<counts<<endl;
system("pause");
return 0;
}

简单来说估计就是这样。
如果要求输出每个学生的等级稍微修改一下就可以了。

Answer 3

具体点，成绩等级的对应关系是什么样的？是否要写成面向对象的？是否要求接口与实现分离？