Question

帮帮忙，都不会写啊

Answer 1

a=1，f(x)=sinx+cosx+b-1=√2sin(x+π/4)+b-1
2kπ-π/2<=x+π/4<=2kπ+π/2，2kπ-3π/4<=x<=2kπ+π/4。
f(x)的单调递增区间是[2kπ-3π/4,2kπ+π/4]。