
java 线程死锁问题
packagethread;//死锁publicclassTestDeadLockimplementsRunnable{privateinti=1;publicstati...
package thread;
//死锁
public class TestDeadLock implements Runnable{
private int i = 1;
public static Object o1 = new Object();
public static Object o2 = new Object();
public void run(){
System.out.println(i);
if(i==1){
synchronized (o1) {
try {
//Thread.sleep(10000);
} catch (Exception e) {
}
}
synchronized (o2) {
System.out.println("先o1");
}
}
if(i==0){
synchronized (o2) {
try {
//Thread.sleep(10000);
} catch (Exception e) {
}
}
synchronized (o1) {
System.out.println("xian o2");
}
}
}
public static void main(String[] args) {
TestDeadLock td1 = new TestDeadLock();
TestDeadLock td2 = new TestDeadLock();
td1.i=1;td2.i=0;
Thread t1 = new Thread(td1);
Thread t2 = new Thread(td2);
t1.start();t2.start();
}
}
这个程序是在培训课上摘抄的,为什么我在Eclipse运行没有产生死锁现象。 展开
//死锁
public class TestDeadLock implements Runnable{
private int i = 1;
public static Object o1 = new Object();
public static Object o2 = new Object();
public void run(){
System.out.println(i);
if(i==1){
synchronized (o1) {
try {
//Thread.sleep(10000);
} catch (Exception e) {
}
}
synchronized (o2) {
System.out.println("先o1");
}
}
if(i==0){
synchronized (o2) {
try {
//Thread.sleep(10000);
} catch (Exception e) {
}
}
synchronized (o1) {
System.out.println("xian o2");
}
}
}
public static void main(String[] args) {
TestDeadLock td1 = new TestDeadLock();
TestDeadLock td2 = new TestDeadLock();
td1.i=1;td2.i=0;
Thread t1 = new Thread(td1);
Thread t2 = new Thread(td2);
t1.start();t2.start();
}
}
这个程序是在培训课上摘抄的,为什么我在Eclipse运行没有产生死锁现象。 展开
2个回答
展开全部
当然不会死锁,i=1时候o1
加了锁,释放后才对o2枷锁,i=2是相反 不会造成等待,要是发生死锁应该这么写
synchronized (o1) {
try {
Thread.sleep(10000);
} catch (Exception e) { }
synchronized (o2) {
System.out.println("先o1");
}
}
下面的也这样,这样才会造成相互等待
加了锁,释放后才对o2枷锁,i=2是相反 不会造成等待,要是发生死锁应该这么写
synchronized (o1) {
try {
Thread.sleep(10000);
} catch (Exception e) { }
synchronized (o2) {
System.out.println("先o1");
}
}
下面的也这样,这样才会造成相互等待
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