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(1)x的-2次方-y的-2次方分之(x的-1次方+y的-1次方)的2次方(2)(xy的-1次方-x的-1次方y)÷(x的-1次方+y的-1次方)(3)(x的2次方-2x...
(1)x的-2次方-y的-2次方分之(x的-1次方+y的-1次方)的2次方
(2)(xy的-1次方-x的-1次方y)÷(x的-1次方+y的-1次方)
(3)(x的2次方-2x+1分之x+1)的-1次方×(x+1分之x-1)的-2次方
计算题【要过程】
结果写成只含有正整数幂的形式 展开
(2)(xy的-1次方-x的-1次方y)÷(x的-1次方+y的-1次方)
(3)(x的2次方-2x+1分之x+1)的-1次方×(x+1分之x-1)的-2次方
计算题【要过程】
结果写成只含有正整数幂的形式 展开
1个回答
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(1) [x^(-1)+y^(-1)]^2/[x^(-2)-y^(-2)]
=[1/x^2+1/y^2+2/(xy)]/(1/x^2-1/y^2)
=[(x^2+2xy+y^2)/(xy)^2]/[(y^2-x^2)/(xy)^2]
=(x+y)^2/(y^2-x^2)
=(x+y)/(y-x)
(2) [xy^(-1)-x^(-1)y]÷[x^(-1)+y^(-1)]
=(x/y-y/x)/(1/x+1/y)
=[(x^2-y^2)/(xy)]/[(x+y)/(xy)]
=x-y
(3) [ (x+1)/(x^2-2x+1)]^(-1)×[(x-1)/(x+1)]^(-2)
=(x-1)^2/(x+1)×[(x+1)^2/(x-1)^2]
=x+1
=[1/x^2+1/y^2+2/(xy)]/(1/x^2-1/y^2)
=[(x^2+2xy+y^2)/(xy)^2]/[(y^2-x^2)/(xy)^2]
=(x+y)^2/(y^2-x^2)
=(x+y)/(y-x)
(2) [xy^(-1)-x^(-1)y]÷[x^(-1)+y^(-1)]
=(x/y-y/x)/(1/x+1/y)
=[(x^2-y^2)/(xy)]/[(x+y)/(xy)]
=x-y
(3) [ (x+1)/(x^2-2x+1)]^(-1)×[(x-1)/(x+1)]^(-2)
=(x-1)^2/(x+1)×[(x+1)^2/(x-1)^2]
=x+1
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