Question

android出现如下错误，求解答

public class SendMessage extends ActionBarActivity {
private Button myButton3 = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.information);
myButton3 = (Button)findViewById(R.id.button2);
myButton3.setOnClickListener(new MyButtonListener());
}
class MyButtonListener implements OnClickListener{
public void onClick(View v) {
String phoneNo = txtPhoneNo.getText().toString();
String message = txtMessage.getText().toString();
if(phoneNo.length()>0 && message.length()>0){
Log.v("ROGER", "will begin sendSMS");
sendSMS(phoneNo,message);
}
else
Toast.makeText(SendMessage.this, "请重新输入", Toast.LENGTH_LONG).show();

}
private void sendSMS(String phoneNumber , String message)
{
PendingIntent pi = PendingIntent.getActivity(this,0,new Intent(this,SendMessage.class), 0);
Log.v("ROGER", "will init SMS Manager");
SmsManager sms = SmsManager.getDefault();

Log.v("ROGER","will send SMS");
sms.sendTextMessage(phoneNumber, null, message, pi, null);
}
}
}
第一个class中txtPhoneNo:txtPhoneNo cannot be resolved
sendSMS中：getactivity:The method getActivity(Context, int, Intent, int) in the type PendingIntent is not applicable for the arguments (SendMessage.MyButtonListener, int, Intent, int)
The constructor Intent(SendMessage.MyButtonListener, Class<SendMessage>) is undefined
求大神解答

Answer 1

1、txtPhone 没有定义
2、PendingIntent pi = PendingIntent.getActivity(this,0,new Intent(this,SendMessage.class), 0);中的两个 this 都改成 MainActivity.this

Answer 2

刷机不成，扔掉吧

追问

？？？

Answer 3

机型？

追问

发送短信需要机型么？？我是中兴GTE手机

Answer 4

恢复出厂设置什么的试试吧 实在不行只能换掉

Answer 5

你这是玩编程？