
展开全部
select * from table where course_id = 'CS-101' group by id having id not in(select id from table where course_id != 'CS-190' group by id)
追问
empty set....
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询
select * from table where course_id = 'CS-101' group by id having id not in(select id from table where course_id != 'CS-190' group by id)
empty set....
类别
我们会通过消息、邮箱等方式尽快将举报结果通知您。
说明
0/200