Question

C++求源代码：定义复数类的一个友元函数 complex add(complex x,complex y)，用于完成两个复数的加法

Answer 1

以前自己写的简单复数运算类。

gcc, Microsoft Visual Studio 2010, 2013编译通过

complex.h(声明)

#include<iostream>
using namespace std;

class Complex
{
private:
	double real;
	double imag;

public:
	Complex(double r=0,double i=0);

	friend Complex operator + (Complex &,Complex &);
	friend Complex operator + (double,Complex &);
	friend Complex operator + (Complex &,double);

	friend Complex operator - (Complex &,Complex &);
	friend Complex operator - (double,Complex &);
	friend Complex operator - (Complex &,double);

	friend ostream &operator <<(ostream &,Complex &);
};

complex.cpp(定义)

#include"complex.h"

Complex::Complex(double r,double i)
{
	real=r;
	imag=i;
}

Complex operator + (Complex &c1,Complex &c2)
{
	Complex ct;
	
	ct.real=c1.real+c2.real;
	ct.imag=c1.imag+c2.imag;

	return ct;
}

Complex operator + (double r,Complex &c)
{
	Complex ct;
	
	ct.real=r+c.real;
	ct.imag=c.imag;

	return ct;
}

Complex operator + (Complex &c,double r)
{
	Complex ct;
	
	ct.real=r+c.real;
	ct.imag=c.imag;

	return ct;
}

Complex operator - (Complex &c1,Complex &c2)
{
	Complex ct;
	
	ct.real=c1.real-c2.real;
	ct.imag=c1.imag-c2.imag;

	return ct;
}

Complex operator - (double r,Complex &c)
{
	Complex ct;
	
	ct.real=r-c.real;
	ct.imag=-c.imag;

	return ct;
}

Complex operator - (Complex &c,double r)
{
	Complex ct;
	
	ct.real=c.real-r;
	ct.imag=c.imag;

	return ct;
}

ostream &operator <<(ostream &os,Complex &c)
{
	if(c.real==0)
	{
		if(c.imag==0)
		{
			os<<0;
		}
		else
		{
			os<<c.imag<<'i';
		}
	}
	else
	{
		if(c.imag==0)
		{
			os<<c.real;
		}
		else if(c.imag>0)
		{
			os<<c.real<<'+'<<c.imag<<'i';
		}
		else
		{
			os<<c.real<<c.imag<<'i';
		}
	}

	return os;
}

Answer 2

建议到论坛里面找人给你看啊