Question

Android HTTPPOST请求报错

public void register(String url,String userName,String passWord){ new AsyncTask<String, Void, String>(){ @Override protected String doInBackground(String... params) { //分别获取三个参数 1.POST请求地址 2.用户名 3.密码 String url = params[0]; String userName = params[1]; String passWord = params[2]; //建立POST请求 HttpPost post = new HttpPost(url);

try { //POST请求需要接收表单，所以用List作为表单 List<BasicNameValuePair> list = new ArrayList<BasicNameValuePair>(); list.add(new BasicNameValuePair("userName",userName)); list.add(new BasicNameValuePair("passWord",passWord)); post.setEntity(new UrlEncodedFormEntity(list)); } catch (UnsupportedEncodingException e) { // TODO Auto-generated catch block e.printStackTrace(); } //HttpResponse try { HttpResponse response = client.execute(post); String result = EntityUtils.toString(response.getEntity()); resultTextView.setText(result); } catch (ClientProtocolException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } return null; } }.execute(url);

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Answer 1

应该是你的post里没有参数

没有封闭请肢早衡求正文,即睁含表单
所以服务历做器没有取到值

追问

为什么post里面没有参数？不是传入了HttpPost post = new HttpPost(url);吗？
表单也有啊 List list = new ArrayList();