高数求导求详细思路步骤
2个回答
展开全部
dy/dx = [2-e^(x+y)]/[1+e^(x+y)]
d^2y/dx^2
=-( [1+e^(x+y)] +[2-e^(x+y)] ). e^(x+y) (1+dy/dx) /[(1+e^(x+y))]^2
=-3e^(x+y) (1+dy/dx) /[(1+e^(x+y))]^2
=-3e^(x+y) (1+[2-e^(x+y)]/[1+e^(x+y)] ) /[(1+e^(x+y))]^2
=-3e^(x+y) ( [1+e^(x+y)]+[2-e^(x+y)] ) /[(1+e^(x+y))]^3
=-9e^(x+y) /[(1+e^(x+y))]^3
d^2y/dx^2
=-( [1+e^(x+y)] +[2-e^(x+y)] ). e^(x+y) (1+dy/dx) /[(1+e^(x+y))]^2
=-3e^(x+y) (1+dy/dx) /[(1+e^(x+y))]^2
=-3e^(x+y) (1+[2-e^(x+y)]/[1+e^(x+y)] ) /[(1+e^(x+y))]^2
=-3e^(x+y) ( [1+e^(x+y)]+[2-e^(x+y)] ) /[(1+e^(x+y))]^3
=-9e^(x+y) /[(1+e^(x+y))]^3
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询