高中数学题,求学霸指导
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把23π/6按照所给规律一直变到0到π上,再根据已知条件和三角诱导公式计算
f(23π/6)=f(π+17π/6)
=f(17π/6)+sin(17π/6)=f(17π/6)+sin(3π-π/6)=f(17π/6)+1/2
=f(π+11π/6)+1/2
=f(11π/6)+sin(11π/6)+1/2=f(11π/6)-1/2+1/2
=f(π+5π/6)-1/2+1/2
=f(5π/6)+sin(5π/6)-1/2+1/2
=0+1/2-1/2+1/2
=1/2
f(23π/6)=f(π+17π/6)
=f(17π/6)+sin(17π/6)=f(17π/6)+sin(3π-π/6)=f(17π/6)+1/2
=f(π+11π/6)+1/2
=f(11π/6)+sin(11π/6)+1/2=f(11π/6)-1/2+1/2
=f(π+5π/6)-1/2+1/2
=f(5π/6)+sin(5π/6)-1/2+1/2
=0+1/2-1/2+1/2
=1/2
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高中数学就是要多练,高考时由于我丰富的做题经验,蒙对了2道选择和一道填空
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