Question

angularjs filter如何筛选

数据类型var arr = [{id: 1, value: "test1"}, {id: 2, value: "test2"}, {id: 3, value: "test3"}, {id: 4, value: "test4"}]。
如果是找到id=3的,{{arr | filter: {id: 3}: true}}就可以了，如果要找到3和4的，如何写？
{{arr | filter: {id: 3}: true | filter: {id: 4}: true}}这样是与的关系，筛选出来的数据是空，如何筛选出或的关系？

Answer 1

{{ [{"age": 20,"id": 10,"name": "iphone"},
{"age": 12,"id": 11,"name": "sunm xing"},
{"age": 44,"id": 12,"name": "test abc"}
] | filter:'s'}} //查找含有有s的行

//上例结果：[{"age":12,"id":11,"name":"sunm xing"},{"age":44,"id":12,"name":"test abc"}]

{{ [{"age": 20,"id": 10,"name": "iphone"},
{"age": 12,"id": 11,"name": "sunm xing"},
{"age": 44,"id": 12,"name": "test abc"}
] | filter:{'name':'iphone'} }} //查找name为iphone的行

//上例结果:[{"age":20,"id":10,"name":"iphone"}]

追问

我想要结果是 age : 20 及 age: 44的 该如何写filter这里？