"ajax"怎么传递多个数值？
jquery 的ajax 向后台传递多个数值时可按一下方法操作。
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script src="js/Jquery1.7.js" type="text/javascript"></script>
<script type="text/javascript">
$(function () {
$('#Button1').click(function () {
var username = $('#txtUserName').val();
var pwd = $('#txtPwd').val();
$.ajax({
type: "post",
contentType: "application/json",
url: "WebService1.asmx/Login",
data: "{username:'" + username + "',pwd:'" + pwd + "'}",
success: function (bukeyi) {
if (bukeyi.d == 'true') {
window.location = 'HTMLPage1.htm';
}
else {
$('#divinfo').text("用户名或密码错误");
}
}
})
})
})
</script>
</head>
<body>
用户名<input id="txtUserName" type="text" /><br />
密码<input id="txtPwd" type="text" /><br />
<input id="Button1" type="button" value="登录" /><br />
<div id="divinfo"></div>
</body>
</html>
方法：
$.ajax({
alert(id);
url: 'aaa.php?act=updact',
type: 'POST',data: "id=" + id + "&name="+$("#name").val(),
success: function(msg) {
alert(msg);window.location.href='caixi.php?act=upd&id='+obj;
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