Question

c语言求2-4+6-8+...-100的值？

Answer 1

#include <stdio.h>

#include <math.h>

int main() {

    int i;

    int sum = 0;

    for(i=1;i<=50;i++) {

        sum += (-2) * i * (pow(-1, i));

    }

    printf("%d\n", sum);

    return 0;

}

Answer 2

您好，程序如下

---

#include <stdio.h>

int main()

{

int sign=1,i,sum=0;

for(i=2;i<=100;i+=2)

{

sum+=sign*i;

sign=-sign;

}

printf("%d\n",sum);

}

---

采纳哦~