等比,有a 2/a 1 = a 4/a 2,代入a1=2,a 4*2=2a 2,等差数列,a 2=2+d,a 4=2+3d,得出d=2,通项为an=2+2(n-1)=2n(n≥1)
,展开bn先看,b1=1/2*1/2,b2=1/3*1/4,b3=1/4*1/6,b4=1/5*1/8-----
n项和sn=++++++,提出1/2,=1/2(1/2+1/3*1/2+1/4*1/3+1/5*1/4+------+1/(n+1*1/n))=1/2(1/2+1/2-1/3+1/3-1/4+1/4-1/5+------+1/n-1/(n+1))合并有sn=1/2(1-1/(n+1))=1/2(n/n+1)