
初二数学,麻烦哪位学长学姐做一下,谢谢
1个回答
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x³+1=(x+1)(x²-x+1)
x³-1=(x-1)(x²+x+1)
x³+2x²+2x+1=x³+1+2x(x+1)=(x+1)(x²-x+1)+2x(x+1)=(x+1)(x²+x+1)
x³-2x²+2x-1=(x-1)(x²+x+1)-2x(x-1)=(x-1)(x²-x+1)
∴原式
=1+1-2(X²+1)/(X²-1)
=2[1-(X²+1)/(X²-1)]
=2[(X²-1-X²-1]/(X²-1)
=-4/(X²-1)
x³-1=(x-1)(x²+x+1)
x³+2x²+2x+1=x³+1+2x(x+1)=(x+1)(x²-x+1)+2x(x+1)=(x+1)(x²+x+1)
x³-2x²+2x-1=(x-1)(x²+x+1)-2x(x-1)=(x-1)(x²-x+1)
∴原式
=1+1-2(X²+1)/(X²-1)
=2[1-(X²+1)/(X²-1)]
=2[(X²-1-X²-1]/(X²-1)
=-4/(X²-1)
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