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(1) since α is in the first quadrant s.t. sinα=1/3
so cosα=2√2/3
since β is in the fourth quadrant s.t. cosβ=3/4
so sinβ=-√7/4
thus cos(α -β)=cosαcosβ-sinαsinβ=(6√2+√7)/12
(2)sorry I dont know how to factorize it
(这题是要你求f(x)=0的根并保留一位小数,我能想到的是对他因式分解后求,但我不会分
如果可以用计算机的话我会用牛顿迭代法去求,但很难想象这是高中生的习题)
(3)the cross product of these two vectors is (8,-7,-9)
(4)according to the law of cosines, c2=a2+b2-2abcosc, so c=10√21
(5)move 1 unit to right along the x axis
so cosα=2√2/3
since β is in the fourth quadrant s.t. cosβ=3/4
so sinβ=-√7/4
thus cos(α -β)=cosαcosβ-sinαsinβ=(6√2+√7)/12
(2)sorry I dont know how to factorize it
(这题是要你求f(x)=0的根并保留一位小数,我能想到的是对他因式分解后求,但我不会分
如果可以用计算机的话我会用牛顿迭代法去求,但很难想象这是高中生的习题)
(3)the cross product of these two vectors is (8,-7,-9)
(4)according to the law of cosines, c2=a2+b2-2abcosc, so c=10√21
(5)move 1 unit to right along the x axis
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