Question

(a-2)^2-(a+1)(a-2)怎么计算

分式计算
2/(a+1)- [(a-2)/(a^2-1)] / [(a^2-2a)/(a^2-2a+1)]

Answer 1

2/(a+1)- [(a-2)/(a^2-1)] / [(a^2-2a)/(a^2-2a+1)]
=2/(a+1)- (a-2)/(a+1)(a-1)*(a-1)/a(a-2)
=2/(a+1)- (a-1)/a(a+1)
=(a+1)/a(a+1)
=1/a