
求助C#连接SQLITE出现错误
1个回答
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你好,我来回答你:
System.Data.SQLite.SQLiteConnection conn =new System.Data.SQLite.SQLiteConnection(@"Data Source=d:\maindb.db;Version=3");
string datasource = "d:\\maindb.db";
//连接数据库
System.Data.SQLite.SQLiteConnection conn =new System.Data.SQLite.SQLiteConnection();
System.Data.SQLite.SQLiteConnectionStringBuilder connstr = new System.Data.SQLite.SQLiteConnectionStringBuilder();
connstr.DataSource = datasource;
conn.ConnectionString = connstr.ToString();
conn.Open();
System.Data.SQLite.SQLiteCommand cmd = new System.Data.SQLite.SQLiteCommand();
//取出数据
string sql = "SELECT * FROM Source";
cmd.CommandText = sql;
System.Data.SQLite.SQLiteDataReader reader = cmd.ExecuteReader();
StringBuilder sb = new StringBuilder();
while (reader.Read())
{
sb.Append("ID:").Append(reader.GetString(0)).Append("\n")
.Append("NAME:").Append(reader.GetString(1));
}
MessageBox.Show(sb.ToString());
如你还有别的问题,可另外向我求助,还有不懂的地方,请继续追问。
System.Data.SQLite.SQLiteConnection conn =new System.Data.SQLite.SQLiteConnection(@"Data Source=d:\maindb.db;Version=3");
string datasource = "d:\\maindb.db";
//连接数据库
System.Data.SQLite.SQLiteConnection conn =new System.Data.SQLite.SQLiteConnection();
System.Data.SQLite.SQLiteConnectionStringBuilder connstr = new System.Data.SQLite.SQLiteConnectionStringBuilder();
connstr.DataSource = datasource;
conn.ConnectionString = connstr.ToString();
conn.Open();
System.Data.SQLite.SQLiteCommand cmd = new System.Data.SQLite.SQLiteCommand();
//取出数据
string sql = "SELECT * FROM Source";
cmd.CommandText = sql;
System.Data.SQLite.SQLiteDataReader reader = cmd.ExecuteReader();
StringBuilder sb = new StringBuilder();
while (reader.Read())
{
sb.Append("ID:").Append(reader.GetString(0)).Append("\n")
.Append("NAME:").Append(reader.GetString(1));
}
MessageBox.Show(sb.ToString());
如你还有别的问题,可另外向我求助,还有不懂的地方,请继续追问。
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