Question

跪求大神指点, vb.net 的图片鼠标事件 怎么把鼠标单击双击和鼠标按下鼠标放开 分辨出来呢?

Private Sub PictureBox1_MouseDown(sender As Object, e As MouseEventArgs) Handles ctureBox1.MouseDown
Label1.Text = "鼠标按下"
End Sub

Private Sub PictureBox1_MouseUp(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles PictureBox1.MouseUp
Label1.Text = "鼠标放开"
End Sub
Private Sub PictureBox1_MouseDoubleClick(sender As Object, e As MouseEventArgs) Handles PictureBox1.MouseDoubleClick
Label1.Text = "鼠标双击"
End Sub

Private Sub PictureBox1_MouseClick(sender As Object, e As MouseEventArgs) Handles PictureBox1.MouseClick
Label1.Text = "鼠标单击"
End Sub
求大神指点. 怎么把鼠标单击 鼠标双击 鼠标按住和鼠标放开分辨出来呢, 这4个事件同时在的时候 ,
鼠标单击双击 都会进入 鼠标按下 和鼠标放开事件里面 我想实现的是,单击 双击 按住 放开 都操作不同的内容 跪求大神指点 要怎么才能分别开来呢?

Answer 1

单击双击和按下松开本身就是重合的操作，分不开的，你想达到什么样的操作目的？

追问

我想准确的判断出来后传送给接收端达到远程效果

追答

那么对于远程接收端来说，它也会同时接收到单击双击和按下松开的操作，这并不矛盾