Question

负一又六分之一*(六分之一减三分之一)*(负十四分之三)除以0.6？

Answer 1

由题意得知，负一又六分之一可以变为 -7/6, 0.6可以化为3/5
所以 -7/6×（1/6-1/3）×（-3/14）÷3/5
=-7/6×（-1/6）×（-3/14）×5/3
=-5/72

Answer 2

计算方法：[6和1/25减去（8.5减去3/16）除以3.5]乘以（1和1/6加1/3）[6和2/25减去3.5]，乘以（1/6+1/25）-（8.5-3/16）÷3.5]3/16）÷7/2]x[7/6+2/6]=[（151/25）-（133/16）÷7/2]x[9/6]=[（151/25）-（133/16）x2/7]x[3/2]=[151/25-19/8]x[1/2]=[1208/1000-475/1000]x[2/2]=733/1000x3/2=2199/2000

Answer 3

[6又25分之一减(8.5减16分之三)除以3.5]乘(1又6分之一加3分之一)
=[(6+1/25)-(8.5-3/16)÷3.5]x[(1+1/6)+1/3]
=[(151/25)-(17/2-3/16)÷7/2]x[(7/6)+1/3]
=[(151/25)-(136/16-3/16)÷7/2]x[7/6+2/6]
=[(151/25)-(133/16)÷7/2]x[9/6]
=[(151/25)-(133/16)x2/7]x[3/2]
=[151/25-19/8]x[3/2]
=[1208/1000-475/1000]x[3/2]
=733/1000x3/2
=2199/2000

Answer 4

[6又25分之一减(8.5减16分之三)除以3.5]乘(1又6分之一加3分之一)
=[(6+1/25)-(8.5-3/16)÷3.5]x[(1+1/6)+1/3]
=[(151/25)-(17/2-3/16)÷7/2]x[(7/6)+1/3]
=[(151/25)-(136/16-3/16)÷7/2]x[7/6+2/6]
=[(151/25)-(133/16)÷7/2]x[9/6]
=[(151/25)-(133/16)x2/7]x[3/2]
=[151/25-19/8]x[3/2]
=[1208/1000-475/1000]x[3/2]
=733/1000x3/2
=2199/2000

Answer 5

[6又25分之一减(8.5减16分之三)除以3.5]乘(1又6分之一加3分之一)
=[(6+1/25)-(8.5-3/16)÷3.5]x[(1+1/6)+1/3]
=[(151/25)-(17/2-3/16)÷7/2]x[(7/6)+1/3]
=[(151/25)-(136/16-3/16)÷7/2]x[7/6+2/6]
=[(151/25)-(133/16)÷7/2]x[9/6]
=[(151/25)-(133/16)x2/7]x[3/2]
=[151/25-19/8]x[3/2]
=[1208/1000-475/1000]x[3/2]
=733/1000x3/2
=2199/2000