Question

已知,log7为底3的对数等于p.log9为底11的对数等于q,求log77为底27的对数

Answer 1

7^p=3 9^q=11
设所求为m,
77^m=27
(7*11)^m=3^3
(3^(1/p)*9^q)^m=27
3^[(1/p+2q)*m]=3^3
(1/p+2q)*m=3
m=3/(1/p+2q)