200分求解：dom4j 使用XPATH解析。。诡异的问题
我用的是dom4j1.61方法写好了，在mian函数里面调用，没有问题，返回值是正确的。可是在JSP里面new了这个类的对象以后，传入同样的值调用方法，报错-Servle...
我用的是dom4j1.61 方法写好了，在mian函数里面调用，没有问题，返回值是正确的。可是在JSP里面new了这个类的对象以后，传入同样的值调用方法，报错
- Servlet.service() for servlet jsp threw exception
org.dom4j.InvalidXPathException: Invalid XPath expression: '/DYHFILE/yw[@ywid='104']'. Caused by: org/jaxen/dom4j/Dom4jXPath
at org.dom4j.xpath.DefaultXPath.parse(DefaultXPath.java:362)
at org.dom4j.xpath.DefaultXPath.<init>(DefaultXPath.java:59)
at org.dom4j.DocumentFactory.createXPath(DocumentFactory.java:230)
at org.dom4j.tree.AbstractNode.createXPath(AbstractNode.java:207)
at org.dom4j.tree.AbstractNode.selectSingleNode(AbstractNode.java:183)
at com.kmi.fsflash.dyh.queryInfo.Getywname(queryInfo.java:135)
at org.apache.jsp.dyh.page1_jsp._jspService(page1_jsp.java:71)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:98)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:331)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:329)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:265)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:213)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:174)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:874)
at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665)
at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528)
at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:81)
at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:689)
at java.lang.Thread.run(Unknown Source)
我怕是路径的问题，所以我现在改成了绝对路径，可是还是同样的错误。米办法了，200分求解
类比较大，只放一个方法上来
public String Getywname(String ywid){
String filepath = "E:\\Work\\FSBackground\\WebRoot\\common\\DYHdata.xml";
Attribute att = null;
try {
doc = read.read(new File(filepath));
Element n = (Element)doc.selectSingleNode("/DYHFILE/yw[@ywid='"+ywid+"']");
att = n.attribute("ywname");
} catch (DocumentException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
return att.getValue();
}
调用的时候，在main里面调用
queryInfo q= new queryInfo();
q.Getywname("102");
没有问题。
但是在JSP里面写
<%
queryInfo q = new queryInfo();
%>
<body>
<%=q.Getywname("102");%><br>
</body>
就不行了。报上面的错误。
麻烦帮忙看下吧，谢谢了 展开
- Servlet.service() for servlet jsp threw exception
org.dom4j.InvalidXPathException: Invalid XPath expression: '/DYHFILE/yw[@ywid='104']'. Caused by: org/jaxen/dom4j/Dom4jXPath
at org.dom4j.xpath.DefaultXPath.parse(DefaultXPath.java:362)
at org.dom4j.xpath.DefaultXPath.<init>(DefaultXPath.java:59)
at org.dom4j.DocumentFactory.createXPath(DocumentFactory.java:230)
at org.dom4j.tree.AbstractNode.createXPath(AbstractNode.java:207)
at org.dom4j.tree.AbstractNode.selectSingleNode(AbstractNode.java:183)
at com.kmi.fsflash.dyh.queryInfo.Getywname(queryInfo.java:135)
at org.apache.jsp.dyh.page1_jsp._jspService(page1_jsp.java:71)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:98)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:331)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:329)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:265)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:213)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:174)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:874)
at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665)
at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528)
at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:81)
at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:689)
at java.lang.Thread.run(Unknown Source)
我怕是路径的问题，所以我现在改成了绝对路径，可是还是同样的错误。米办法了，200分求解
类比较大，只放一个方法上来
public String Getywname(String ywid){
String filepath = "E:\\Work\\FSBackground\\WebRoot\\common\\DYHdata.xml";
Attribute att = null;
try {
doc = read.read(new File(filepath));
Element n = (Element)doc.selectSingleNode("/DYHFILE/yw[@ywid='"+ywid+"']");
att = n.attribute("ywname");
} catch (DocumentException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
return att.getValue();
}
调用的时候，在main里面调用
queryInfo q= new queryInfo();
q.Getywname("102");
没有问题。
但是在JSP里面写
<%
queryInfo q = new queryInfo();
%>
<body>
<%=q.Getywname("102");%><br>
</body>
就不行了。报上面的错误。
麻烦帮忙看下吧，谢谢了 展开
10个回答
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你看看xml写错没
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<%=q.Getywname("102");%><br>写错了，“；”去掉。是这个原因？
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DeBug一下不就知道了！
换个JSP容器试试
换个JSP容器试试
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真奇怪。。
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你没有写对吧
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