Question

页面跳转的a标签的页码p如何获取到前面input标签中你输入的value值

//分页
//$allCnt 全部数量
//$limit 每页的数量
//$goto 是否添加转到
function getPageHtml($allCnt , $limit = LIMIT , $goto = 1){
$url = '?';
$index = 1;
$size = 1;
if($_SERVER['QUERY_STRING'] != ""){
$url = str_replace($_SERVER['QUERY_STRING'],'',$_SERVER['REQUEST_URI']);
foreach($_GET as $k=>$v){
if($k != "p") $url .= $k.'='.urlencode($v).'&';
}
}
if(isset($_GET['p'])) $index = intval($_GET['p']);
if($limit != 0) $size = ceil($allCnt / $limit);
if($index < 1) $index = 1;
if($index > $size) $index = $size;
$pre = $index - 1;
$nex = $index + 1;
$str = '<div id="jq_table_footer" style="padding:2px"><div style="float:left;">
当前第【{=index=} / {=size=}】页 记录总数【<span id="result_total_count">{=cnt=}</span>】 ';
if($goto == 1){
$str .= '转到 <input size="1" id="p" name="p" class="smallInput" value=""> 页'.'<a href="'.$url.'p="> [跳转]</a>';
}

Answer 1

ShowWindow(hwnd,nShowCmd);
UpdateWindow(hwnd);
while(GetMessage(&msg,NULL,0,0))
TranslateMessage(&msg);
DispatchMessage(&msg);
}
return msg.wParam;
}

追问

这个可以在PHP中用？