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(A) Kevin: 15a-5a/4*1=55a/4
His brother: 5a+5a/4*1=25a/4
(B) As the question asked for same number of cards between Kevin and his brother after certain several times, we can set the time as X. (问题要求凯文与他的哥哥经过几次交换后手上的卡牌数量一样，那我们就设这个次数为X。）
15a-5a/4*X=5a+5a/4*X
10a=2.5a*X
X=4 (4 is integral.)
Yes, it is possible that they have same amount of cards in the meantime after 4 times exchange.
His brother: 5a+5a/4*1=25a/4
(B) As the question asked for same number of cards between Kevin and his brother after certain several times, we can set the time as X. (问题要求凯文与他的哥哥经过几次交换后手上的卡牌数量一样，那我们就设这个次数为X。）
15a-5a/4*X=5a+5a/4*X
10a=2.5a*X
X=4 (4 is integral.)
Yes, it is possible that they have same amount of cards in the meantime after 4 times exchange.
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