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解:∵已知12、4、9、13需运用加、减、乘、除使等式成立
最终结果等于24
根号9 = 正3或负3 舍去-3 ∴根号9 = 3
根号4 = 正2或负2 舍去-2 ∴根号4 = 2
∴[13 - (4 - 根号9)] + 12 = [13 - (4 - 3)] + 12 = (13 - 1)+ 12 = 12 + 12 = 24
[13 - (根号9 - 根号4)] + 12 = [13 - (3 - 2)] + 12 = (13 - 1)+ 12 = 12 + 12 = 24
[(13 - 根号4)- 9 ] × 12 = [(13 - 2)- 9 ] × 12 = (11 - 9)× 12 = 2 × 12 = 24
(13 + 12)- (根号9 - 根号4)= 25 - (3 - 2)= 25 - 1 = 24
[13 +(12 - 4)] + 根号9 = (13 + 8)+ 3 = 21 + 3 = 24
(13 - 4)+ 根号9 + 12 = 9 + 3 + 12 = 12 + 12 = 24
最终结果等于24
根号9 = 正3或负3 舍去-3 ∴根号9 = 3
根号4 = 正2或负2 舍去-2 ∴根号4 = 2
∴[13 - (4 - 根号9)] + 12 = [13 - (4 - 3)] + 12 = (13 - 1)+ 12 = 12 + 12 = 24
[13 - (根号9 - 根号4)] + 12 = [13 - (3 - 2)] + 12 = (13 - 1)+ 12 = 12 + 12 = 24
[(13 - 根号4)- 9 ] × 12 = [(13 - 2)- 9 ] × 12 = (11 - 9)× 12 = 2 × 12 = 24
(13 + 12)- (根号9 - 根号4)= 25 - (3 - 2)= 25 - 1 = 24
[13 +(12 - 4)] + 根号9 = (13 + 8)+ 3 = 21 + 3 = 24
(13 - 4)+ 根号9 + 12 = 9 + 3 + 12 = 12 + 12 = 24
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