Question

C语言编程：利用公式e=1+1/1!+1/2!+```+1/n!计算e的值，要求：最后一项小于10的负6次方，

急 帮帮忙谢谢···

Answer 1

#include<并迹尘州庆stdio.h>
#include<math.h>
double Fun(double n)
{
double f;
if(n<0) printf("data error");
else
if(n==0||n==1) f=1;
else
f=Fun(n-1)*n;
return(f);
}

void main()
{
double t,k=0,x=1;
do{

k+=1.0/Fun(x);
t=1.0/Fun(x);
x++;
}while(t>1e-6);
printf("绝禅%f",k);
}

Answer 2

#include<老神者stdio.h>
main()
{
long int a=1,b=1;
double sum=0;
while(1.0\侍薯瞎梁b>=pow(10,-6))
{ b=a*b;
sum+=1.0\b;
b++;
}
printf("%f",sum);
}

Answer 3

#include "stdio.h"迅冲念
main()
{
int n;
float t=1.0,sum;
for(n=1;;n++)
{
t=t*n;
sum=sum+1/t;
if(1/t<1e-6)
break;
}
printf("判好%f\亩困n",sum);
}

Answer 4

#include<stdio.h>
#include<仿昌嫌math.h>
double fun(double x, double eps){
double sum=1.0,m=1.0,t;
int i=1;
do{
m=m*i;
t=pow(x,1)/m;
sum+=t;
i++;
}while (t>备手eps);
return sum;
}
void main()
{
printf("迅局%f",fun(1,1e-6));
}