Question

C语言程序:写一个函数，输入一个4位数字，要求输出这4个数字字符，每两个数字字符间

对不起是我的大意，是这样的：写一个函数，输入一个4位数字，要求输出这4个数字字符，每两个数字字符间空一个空格。如输入1990，输出“1 9 9 0”

Answer 1

#include <stdio.h>
#include <stdlib.h>

void main()
{
int k;
int i1,i2,i3,i4;

printf("Please enter a data with 4 digits\n");
scanf("%d",&k);
i1 = k % 10;
k = (k - i1) / 10;
i2 = k % 10;
k = (k - i2) / 10;
i3 = k % 10;
k = (k - i3) / 10;
i4 = k;
printf("%d-%d-%d-%d\n",i4,i3,i2,i1); //每两个数字字符间有“-”
exit(0);

}

Answer 2

#include
"stdio.h"
void
main()
{int
n,a[4],m=1000,i;
scanf("%d",&n);
printf("\n");
for(i=0;i<4;i++)
{a[i]=n/m;
n=n-m*a[i];
m=m/10;
printf("%d
",a[i]);}
}

Answer 3

#include<stdio.h>
void main()
{ int x,a[4],i;
scanf("%d",&x); x%=10000;
i=0; while ( x ) { a[i]=x%10; i++; x/=10; }
for ( i=0;i<4;i++ ) printf("%d ",a[3-i]);
printf("\n");

}

Answer 4

#include "stdio.h"
void main()
{int n,a[4],m=1000,i;
scanf("%d",&n);
printf("\n");
for(i=0;i<4;i++)
{a[i]=n/m;
n=n-m*a[i];
m=m/10;
printf("%d ",a[i]);}
}

Answer 5

#include
void
main()
{
int
x,a[4],i;
scanf("%d",&x);
x%=10000;
i=0;
while
(
x
)
{
a[i]=x%10;
i++;
x/=10;
}
for
(
i=0;i<4;i++
)
printf("%d
",a[3-i]);
printf("\n");
}