Question

C++简单字符串问题。。

大大能不能再问你一个问题呀。。。今晚的DDL我怎么也DEBUG不出来啊T.T。。。

#include"stdafx.h"

#include<iostream>

#include<string>

using namespace std;

int main(){

int aver,total=0,l=0,i;

string a;

cout<<"Please input the string:"<<endl;

getline(cin,a,'.');

for(i=0;a[i]!='.';i++)

if(((a[i]>='a'&&a[i]<='z')||(a[i]>='A'&&a[i]<='Z'))&&!((a[i+1]>='a'&&a[i+1]<='z')||(a[i+1]>='A'&&a[i+1]<='Z')))

total++;

for(i=0;a[i]!='.';i++)

if((a[i]>='a'&&a[i]<='z')||(a[i]>='A'&&a[i]<='Z'))

l++;

aver=l/total;

cout<<"The avarage length of the string is "<<aver<<endl;

return 0;

}

求助啊。。。。谢谢你！！！

Answer 1

#include<iostream>

#include<string>

using namespace std;

int main(){

int aver, total = 0, l = 0, i;

string a;

cout << "Please input the string:" << endl;

getline(cin, a, '.');

for (i = 0;i< a.length()-1 ; i++)//a[i] != '.'这里错误

if (((a[i] >= 'a'&&a[i] <= 'z') || (a[i] >= 'A'&&a[i] <= 'Z')) && !((a[i + 1] >= 'a'&&a[i + 1] <= 'z') || (a[i + 1] >= 'A'&&a[i + 1] <= 'Z')))

total++;

for (i = 0; i< a.length(); i++)

if ((a[i] >= 'a'&&a[i] <= 'z') || (a[i] >= 'A'&&a[i] <= 'Z'))

l++;

aver = l / total;

cout << "The avarage length of the string is " << aver << endl;

return 0;

}

追问

谢谢大大！！如果我想输出某句子的平均单词长度，应该怎么改呢。。？

追答

aver你不是求了么

追问

但是是错的啊T.T