Question

跪求大神，用js或者java循环遍历json数组，实现下面功能，太难了，实在不会，跪求了（6）。

//如果是java实现，希望不用javabean做，因为json数组里除了first_id,first_name,second_id,second_name,third_id,third_name 其它属性未知,因为属性是配置在数据库，如果加个属性还要修改代码
由于字数限制 未贴代码

这边有pan.baidu.com/s/1o6p4OaA

Answer 1

var origin = [
{"first_id":1,"first_name":"中学","second_id":"1-1","second_name":"一年级","third_id":"1-1-1","third_name":"一年级一班","people":10,"age":10,"parent":5},
{"first_id":1,"first_name":"中学","second_id":"1-1","second_name":"一年级","third_id":"1-1-2","third_name":"一年级二班","people":11,"age":10,"parent":5},
{"first_id":1,"first_name":"中学","second_id":"1-2","second_name":"二年级","third_id":"1-2-1","third_name":"二年级一班","people":20,"age":10,"parent":5},
{"first_id":1,"first_name":"中学","second_id":"1-2","second_name":"二年级","third_id":"1-2-2","third_name":"二年级二班","people":21,"age":10,"parent":5},
{"first_id":2,"first_name":"高中","second_id":"2-1","second_name":"一年级","third_id":"2-1-1","third_name":"一年级一班","people":31,"age":10,"parent":5}
];

var finalData = []; // 最终的数据

transferData(); // 数据转换
console.log(finalData, JSON.stringify(finalData));

function transferData() {
	origin.forEach(function(n) {
		var first = getRecordById(n.first_id, finalData);
		if (first) {
			first.age += n.age;
			first.parent += n.parent;
			first.people += n.people;

			var second = getRecordById(n.second_id, first.children);
			if (second) {
				second.age += n.age;
				second.parent += n.parent;
				second.people += n.people;

				var third = getRecordById(n.third_id, second.children);
				if (third) {
					// 这里应该不会存在
				} else {
					second.children.push({
						id: n.third_id,
						name: n.third_name,
						age: n.age,
						parent: n.parent,
						people: n.people
					});
				}
			} else {
				first.children.push({
					id: n.second_id,
					name: n.second_name,
					age: n.age,
					parent: n.parent,
					people: n.people,
					children: [{
						id: n.third_id,
						name: n.third_name,
						age: n.age,
						parent: n.parent,
						people: n.people
					}]
				});
			}
		} else {
			finalData.push({
				id: n.first_id,
				name: n.first_name,
				age: n.age,
				parent: n.parent,
				people: n.people,
				children: [{
					id: n.second_id,
					name: n.second_name,
					age: n.age,
					parent: n.parent,
					people: n.people,
					children: [{
						id: n.third_id,
						name: n.third_name,
						age: n.age,
						parent: n.parent,
						people: n.people
					}]
				}]
			});
		}
	});
}

function getRecordById(id, data) {
	for (var i = 0, n = data.length; i < n; i++) {
		if (data[i].id == id) return data[i];
	}
	return null;
}

Answer 2

Answer 3

无外乎就是拼接。。。格式你都清楚了，怎么就拼接不出来

追问

水平菜，可以看看？