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先化简,再求值:2x+1-1x2-1÷xx2-2x+1,其中x=5
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2 |
x+1 |
1 |
x2-1 |
x |
x2-2x+1 |
=
2 |
x+1 |
1 |
(x+1)(x-1) |
(x-1)2 |
x |
=
2 |
x+1 |
x-1 |
x(x+1) |
=
2x |
x(x+1) |
x-1 |
x(x+1) |
=
2x-x+1 |
x(x+1) |
=
x+1 |
x(x+1) |
=
1 |
x |
当x=5时,原式=
1 |
x |
1 |
5 |
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2 |
x+1 |
1 |
x2-1 |
x |
x2-2x+1 |
2 |
x+1 |
1 |
(x+1)(x-1) |
(x-1)2 |
x |
2 |
x+1 |
x-1 |
x(x+1) |
2x |
x(x+1) |
x-1 |
x(x+1) |
2x-x+1 |
x(x+1) |
x+1 |
x(x+1) |
1 |
x |
1 |
x |
1 |
5 |
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