分解因式 a²－11a＋24
2个回答
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a” - 11a + 24
= a” - 3a - 8a + 24
= a( a - 3 ) - 8( a - 3 )
= ( a - 3 )( a - 8 )
或者
= a” - 8a - 3a + 24
= a( a - 8 ) - 3( a - 8 )
= ( a - 3 )( a - 8 )
或者配方
= (1/4)[ 4a” - 11(4a) + 96 ]
= (1/4)[ (2a)” - 11(4a) + 11” - 121 + 96 ]
= (1/4)[ ( 2a - 11 )” - 25 ]
= (1/4)[ ( 2a - 11 )” - 5” ]
= (1/4)( 2a - 11 + 5 )( 2a - 11 - 5 )
= (1/4)( 2a - 6 )( 2a - 16 )
= ( a - 3 )( a - 8 )
= a” - 3a - 8a + 24
= a( a - 3 ) - 8( a - 3 )
= ( a - 3 )( a - 8 )
或者
= a” - 8a - 3a + 24
= a( a - 8 ) - 3( a - 8 )
= ( a - 3 )( a - 8 )
或者配方
= (1/4)[ 4a” - 11(4a) + 96 ]
= (1/4)[ (2a)” - 11(4a) + 11” - 121 + 96 ]
= (1/4)[ ( 2a - 11 )” - 25 ]
= (1/4)[ ( 2a - 11 )” - 5” ]
= (1/4)( 2a - 11 + 5 )( 2a - 11 - 5 )
= (1/4)( 2a - 6 )( 2a - 16 )
= ( a - 3 )( a - 8 )
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