
X的立方减一,可以怎么因式分解
3个回答
展开全部
可以通过添项,再分组分解
x³-1
=x³-x+x-1
=(x³-x)+(x-1)
=x(x²-1)+(x-1)
=x(x+1)(x-1)+(x-1)
=(x-1)[x(x+1)+1]
=(x-1)(x²+x+1)
x³-1
=x³-x+x-1
=(x³-x)+(x-1)
=x(x²-1)+(x-1)
=x(x+1)(x-1)+(x-1)
=(x-1)[x(x+1)+1]
=(x-1)(x²+x+1)
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