Question

用配方法解二元一次方程

用配方法解二元一次方程要写过程，谢谢。拜托了

Answer 1

第1题 x2-6x=4 x2-6x+32=9+4 (x-3)2=13 x-3=±√13 x=3±√13 第2题 x2-5x=-2 x2-5x+(5/2)2=25/4-2 (x-5/2)2=17/4 x-5/2=±√17/2 x=5/2±√17/2

Answer 2

(1)
x^2+3x+1=0
(x+ 3/2)^2 = 5/4
x+ 3/2 = √5/2 or -√5/2
x= (-3+√5)/2 or (-3-√5)/2
(2)
x^2+4√2x-1=0
(x+ 2√2)^2 = 9
x+ 2√2 = 3 or -3
x=3-2√2 or -3-2√2