Question

求第33题，要过程，特别是limx→0￣

Answer 1

f(0)=b
f(0-)

=lim(x->0-) x.√(2-2cosx)/{ 2.∫(0->x) [√(1+sint) -1 ] dt }
=lim(x->0-) x.sin(x/2)/{ 2.∫(0->x) [√(1+sint) -1 ] dt }
=(1/4)lim(x->0-) x^2/∫(0->x) [√(1+sint) -1 ] dt
(0/0 分子分母分别求导)
=(1/4)lim(x->0-) 2x/ [√(1+sinx) -1 ]
=(1/4) lim(x->0-) 2x. [√(1+sinx) +1 ] / sinx
=(1/4)lim(x->0-) 2 [√(1+sinx) +1 ]
=1
f(0+)

=lim(x->0+) ax^x = a
=>

a=b=1

追问

谢谢，可是答案是-2😓

我知道你的意思