2x²-xy-2y²因式分解?
3个回答
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原式=2x^2-xy+(1/2)y^2-(5/2)y^2
=(√2x-y/伍升√2)^2-(5/2)y^2
=(√2x-y/√2+√5y/√2)(√2x-y/√裂雀2-√5y/√2)
=[√2x+(√5-1)y/√2][√2x-(√5+1)y/√2]
=2[x+(√5-1)y/腔源老2][x-(√5+1)y/2]
=(√2x-y/伍升√2)^2-(5/2)y^2
=(√2x-y/√2+√5y/√2)(√2x-y/√裂雀2-√5y/√2)
=[√2x+(√5-1)y/√2][√2x-(√5+1)y/√2]
=2[x+(√5-1)y/腔源老2][x-(√5+1)y/2]
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展开全部
2x 2 xy-2y 2全歼纳部展开
=2(x xy/2)-2y
=2(x y/2) -2×(y /4)-2y
=2(x y/氏空没亏陵2) -10y /4
=2[(x y/2) -5y /4]
= 2[(x y/2)(y√5)/2][(x y/2)-(y√5)/2]
=2[x (1 √5)y/2][x (1-√5)y/2]
=2(x xy/2)-2y
=2(x y/2) -2×(y /4)-2y
=2(x y/氏空没亏陵2) -10y /4
=2[(x y/2) -5y /4]
= 2[(x y/2)(y√5)/2][(x y/2)-(y√5)/2]
=2[x (1 √5)y/2][x (1-√5)y/2]
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