Question

计算矩形面积 用java

当有一个参数输入时，确认为正方形，两个参数时为长方形；
建立一个求面积的类，使用方法的重载和构造方法两种思路完成代码。

Answer 1

方法的重载

class Circle
{
private float a;
private float b;
public float area;
public void setA(float a)
{
this.a=a;
}
public float getA()
{
return this.a;
}
public void setArea(float b)
{
this.b=b;
}
public float getB()
{
return this.b;
}
public void into(float a)
{
area=a*a;
System.out.println("这是一个正方形...面积为: "+area);
}
public void into(float a,float b)
{
area=a*b;
System.out.println("这是一个正方形...面积为: "+area);
}
}
public class Java
{
public static void main(String args[])
{
Circle c=new Circle();
c.into(2);
c.into(2,3);
}
}

Answer 2

//重载
public class TestCount {

public static void main(String[] args) {
System.out.println(count(5));
System.out.println(count(6,7));
}

public static float count(float a)
{
float area = a*a;
return area;
}

public static float count(float a, float b)
{
float area = a*b;
return area;
}
}

构造方法是为了初始化对象。
public class Count {
double width,height;
Count (double w){
width=w;
}
Count (double w,double h){
width=w;
height=h;
}
double square(){
return width*width;
}
double rectangular(){
return width*height;
}
}