已知（x+1)的5次方=ax的5次方+bx的4次方+cx的3次方+dx的平方+ex+f,求下列各式的值
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(x+1)^5 = x^5 + 5x^4 + 10x^3 + 10x^2 + 5x + 1
a = 1, b = 5, c = 10, d = 10, e = 5, f = 1,
a + b + c + d + e + f = (1+1)^5 = 32
b + c + d + e = 5 + 10 + 10 + 5 = 30
a + c + e = 1 + 10 + 1 = 12
a = 1, b = 5, c = 10, d = 10, e = 5, f = 1,
a + b + c + d + e + f = (1+1)^5 = 32
b + c + d + e = 5 + 10 + 10 + 5 = 30
a + c + e = 1 + 10 + 1 = 12
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