Question

高一数学

（lg1+lg2+lg4+lg8+~~~~~~~~~~~+lg1024)*log
32 10
请给出具体步骤

Answer 1

(lg1+lg2+lg4+lg8+......+lg1024)*log(32)10
=(lg2^0+lg2^1+lg2^2+……+lg2^10)*(lg10/lg32)
=(0*lg2+1*lg2+2*lg2+……+10*lg2)*(1/lg2^5)
=lg2*(0+1+2+……+10)*(1/5lg2)
=55*1/5
=11

Answer 2

原式=[log2 1/log2 10+log2 2¹/log2 10……+lg2 2^10/log2 10]
*[log2 10/log2 2^5]
=[(1+2+3+……+10)/log2 10]*[log2 10/5]
=55/5
=11

Answer 3

lg1+lg2+lg4+lg8+~~~~~~~~~~~+lg1024=lg(1*2*2^2*2^3*~~~~~*2^12)

Answer 4

32 10 ？？？看不懂！！！

Answer 5