Question

已知a,b为实数,且根号a-5+2根号10-2a=b+4,求a,b,的值

Answer 1

(a-5)^(1/2) + 2(10-2a)^(1/2) = b + 4,

a - 5 >= 0,
10-2a >= 0,

a = 5.

b + 4 = 0. b = -4.

Answer 2

因为a-5和10-2a都在根号下，所以
a-5>=0, 10-2a>=0, 即a>=5, a<=5, 所以a=5.
代入，0+0=b+4, b=-4.