Question

c语言编写一个程序，输入10个数分别求出数组中所有奇数之和以及所有偶数之和

Answer 1

#include<iostream>

using namespace std;

int main()
{
int a,i,sumj=0,sumo=0;
for (i=0;i<10;i++)
{
cin>>a;
if (a%2==0)
sumo=sumo+a;
else
sumj=sumj+a;
}
cout<<"奇数的个数是"<<sumj<<endl;
cout<<"偶数的个数是"<<sumo<<endl;
return 0;
}

Answer 2

void main()
{int sumj=0,sumo=0,get,i;
printf("please input 10 numbers:\n");
for(i=0;i<10;i++)
{
scanf("%d",&get);
if(get%2==0)
sumo+=get;
else sumj+=get;
}
printf("jishuhe %d,oushuhe %d",sumj,sumo);
getch();
}
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十个数字用空格隔开