sin50°(1+根号3tan10°)的值????在线求解!!!!详细过程。看懂就采纳!!!
2个回答
展开全部
sin50°(1+√3·tan10°)
=sin50°×(1+tan60°tan10°)
=sin50°(tan60°-tan10°)/tan(60°-10°)
=cos50°(tan60°-tan10°)
=cos50°(sin60°cos10°-sin10°cos50°)/cos60°cos10°
=cos50°sin50°/cos60°cos10°
=1/2 ×sin100° /cos60°cos10°
=1/2 ×cos10°/(1/2×cos10°)
=cos10°/cos10°
=1
=sin50°×(1+tan60°tan10°)
=sin50°(tan60°-tan10°)/tan(60°-10°)
=cos50°(tan60°-tan10°)
=cos50°(sin60°cos10°-sin10°cos50°)/cos60°cos10°
=cos50°sin50°/cos60°cos10°
=1/2 ×sin100° /cos60°cos10°
=1/2 ×cos10°/(1/2×cos10°)
=cos10°/cos10°
=1
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询