sin50°(1+根号3tan10°)的值????在线求解!!!!详细过程。看懂就采纳!!!
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sin50°(1+√3·tan10°)
=sin50°×(1+tan60°tan10°)
=sin50°(tan60°-tan10°)/tan(60°-10°)
=cos50°(tan60°-tan10°)
=cos50°(sin60°cos10°-sin10°cos50°)/cos60°cos10°
=cos50°sin50°/cos60°cos10°
=1/2 ×sin100° /cos60°cos10°
=1/2 ×cos10°/(1/2×cos10°)
=cos10°/cos10°
=1
=sin50°×(1+tan60°tan10°)
=sin50°(tan60°-tan10°)/tan(60°-10°)
=cos50°(tan60°-tan10°)
=cos50°(sin60°cos10°-sin10°cos50°)/cos60°cos10°
=cos50°sin50°/cos60°cos10°
=1/2 ×sin100° /cos60°cos10°
=1/2 ×cos10°/(1/2×cos10°)
=cos10°/cos10°
=1
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