Question

怎样用C#读取以下txt文件的数据，能把数据分开存储在不同数组中

1 1.00000400000000e-07 -2.00001600000000e-12
2 1.00001600000000e-07 -4.00012800000000e-12
3 1.00003600000000e-07 -6.00043200000000e-12
4 1.00006400000000e-07 -8.00102400000000e-12
5 1.00010000000000e-07 -1.00020000000000e-11
6 1.00014400000000e-07 -1.20034570000000e-11
7 1.00019600000000e-07 -1.40054890000000e-11
8 1.00025600000000e-07 -1.60081950000000e-11
9 1.00032410000000e-07 -1.80116690000000e-11
10 1.00040010000000e-07 -2.00160090000000e-11
文件格式如上，数据之间隔的是/t，请问如何读取

Answer 1

List<string> column0 = new List<string>();
List<string> column1 = new List<string>();
List<string> column2= new List<string>();
using(StreamReader r = new StreamReader("test.txt"))
{
    string line = r.ReaderLine();
    string[] columns = null;

    while(line!=""&&line!=null)
    {
        columns = line.Split('\t');
        column0.Add(columns[0]);
        column1.Add(columns[1]);
        column2.Add(columns[2]);
        line = r.ReadLine();
    }
}